Program to Read a String From the User and Print It Using a Character Pointer

• C++ program to accept array input and print using For loop
  • Code to read input and print of  assortment elements
    • Code to take input and print integer of an array using for loop
    • Code to take input and impress String of an array using for loop
    • Code to accept input and print graphic symbol of an assortment using for loop

C++ program to accept assortment input and impress using For loop

In this article, nosotros will discuss the concept of C++ program to accept array input and print using For loop

In this postal service, we are going to larn how to write a programme to read array input and impress given elements of an assortment using for loop in C++ language

Code to read input and print of  array elements

Code to have input and print integer of an array using for loop

In this code, we are going to learn how to read integer array input given by user and print the them using for loop in C++ linguistic communication

Program 1

#include <iostream> #include <conio.h> using namespace std;  int main() {     int i,len;     //integer variable announcement     cout<<"Enter the Array length: ";     //Ask input for array length       cin>>len;       //Reading the input for array length     int num[len]; //Array declaration       cout<<"\n";//move to next line         cout<<"Enter the Number for assortment :";        //Ask input for elements(numbers)     for(i=0; i<len; i++){//input using for loop       cin>>num[i];       //Reading the assortment elements from user     }     cout<<"\ndisplay the number\northward";       for(i=0; i<len; i++){//display elements using for loop       cout<<num[i];       cout<<("\n");     } getch();     return 0; }          

When the to a higher place code is executed, it produces the post-obit result

have array input and impress

Programme 2

#include <iostream> #include <conio.h> using namespace std;  int main() {     int i,len;//integer variable declaration     cout<<"Enter the Array length: ";     //Ask input from the user for array length       cin>>len;       //Reading the input for array length     int marks[len]; //Assortment announcement - integer       cout<<"\northward";//move to next line          //Ask input for elements(number)     for(i=0; i<len; i++){//input using for loop             cout<<"Enter the marks "<<"marks["<<i<<"] :";       cin>>marks[i];       //Reading the array elements from user     }     cout<<"\ndisplay the marks\due north";       for(i=0; i<len; i++){//display elements using for loop       cout<<"marks["<<i<<"] :"<<marks[i];       cout<<("\n");     } getch();     render 0; }          

When the above lawmaking is executed, it produces the following upshot

Enter the array length: 5  Enter the marks marks[0]: 46 Enter the marks marks[1]: 78 Enter the marks marks[2]: 94 Enter the marks marks[three]: 36 Enter the marks marks[4]: 50   Brandish the marks  marks[0]=46 marks[1]: 78 marks[2]: 94 marks[three]: 36 marks[four]: 50

Code to accept input and print String of an assortment using for loop

In this lawmaking, we are going to learn how to read string array input given by user and print  them using for loop in C++ language

Program 1

#include <iostream> #include <conio.h> using namespace std;  int main() {     string str[20];     //Single D assortment declaration     int len;//Declare variable for length     cout<<"Enter array length\due north";     //Inquire input from the user for length     cin>>len; //Reading the input for length     cout<<"\nEnter students name\north";     //Ask enter the student proper noun     for(int i=0; i<len; i++){         cin>>str[i];     }//Enter the students name using for loop      cout<<"\nEntered students names are:\north";     for(int i=0;  i<len; i++){         cout<<str[i]<<"\n";         //Display the students name     }       getch();     return 0; }          

When the above code is executed, information technology produces the following effect

accept assortment input and print

Program 2

#include <iostream> #include <conio.h> using namespace std;  int main() {     string str[20];     //Unmarried D array declaration     int len;//Declare variable for length     cout<<"Enter assortment length\north";     //Enquire input from the user for length     cin>>len; //Reading the input for length     cout<<"\nEnter students name\north";     //Ask enter the student name     for(int i=0; i<len; i++){         cout<<"Enter the string"<<" str=["<<i<<"]: ";         cin>>str[i];     }//Enter the students name using for loop      cout<<"\nEntered students names are:\north";     for(int i=0;  i<len; i++){             cout<<"Your entered cord is:"<<" str=["<<i<<"]: ";         cout<<str[i]<<"\n";         //Display the students proper name     }     getch();     return 0; }          

When the above code is executed, it produces the following result

Accept array input and impress

Code to take input and print character of an array using for loop

In this code, nosotros are going to learn how to read character assortment input given by user and print the them using for loop in C++ language

Programme 1

#include <iostream> #include <conio.h> using namespace std;  int main() {     int i,len;     //integer variable announcement     cout<<"Enter the Array length: ";     //request input for array length       cin>>len;       //Reading the input for array length     char char_array[len]; //declare grapheme Array       cout<<"\n";       //move to next line         cout<<"Enter the characters for array :";        //Request input for elements(numbers)     for(i=0; i<len; i++){//input using for loop       cin>>char_array[i];       //Reading the array elements from user     }     cout<<"\ndisplay the characters\n";       for(i=0; i<len; i++){//print elements using for loop       cout<<char_array[i];       cout<<("\n");     } getch();     return 0; }          

When the above code is executed, it produces the following result

Enter the array length:x  Enter the characters for array :Code4javac display the characters  C o d e 4 j a v a c          

Program 2

#include <iostream> #include <conio.h> using namespace std;  int principal() {     int i,len;     //variable proclamation - integer     cout<<"Enter the Array length: ";     //request input for array length       cin>>len;       //Reading the input for array length     char char_array[len]; //Array annunciation - char array       cout<<"\n";//movement to adjacent line        cout<<"Enter the characters for array :\due north";        //Ask input for elements(numbers)     for(i=0; i<len; i++){//input using for loop     cout<<"char_array["<<i<<"]:";       cin>>char_array[i];       //Reading the array elements from user     }     cout<<"\ndisplay the characters\n";       for(i=0; i<len; i++){//display elements using for loop       cout<<"char_array["<<i<<"]:"<<char_array[i];       cout<<("\due north");     } getch();     return 0; }          

When the above code is executed, it produces the post-obit event

Accept array input and impress

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Program to Read a String From the User and Print It Using a Character Pointer

Source: https://code4javac.com/2021/07/23/c-program-to-accept-array-input-and-print-using-for-loop/

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